First slide

Magnetic dipole in a uniform magnetic field

Question

At a certain place a magnet makes 30 oscillations per minute. At another place where the magnetic field is doubled its time period will be

Difficult

A

4 sec
B

2 sec
C

1/2 sec
D

$\sqrt{2}$ sec

Solution

T = (60 / 30) = 2sec.
We know that $T = 2 π \sqrt{(\frac{I}{MH})}$
Further $T^{'} = 2 π \sqrt{\{\frac{I}{M (2 H)}\}} = \frac{1}{\sqrt{2}} [T] = \frac{2}{\sqrt{2}} = \sqrt{2} \sec .$

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