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Q.

In a certain place on the surface of earth, angle of dip in a vertical plane ‘P’ is 300 . At the same place, angle of dip in another vertical plane ‘Q’ which is perpendicular to the plane. ‘P’, is  600. Then true angle of dip at that place is

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a

tan−123

b

tan−1710

c

tan−134

d

tan−1310

answer is D.

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Detailed Solution

If true angle of dip at that place is δ , thencot2δ   =   cot2δp+cot2δQ           = cot2300+cot2600           = 3+13 = 103    ∴ δ = tan−1310Magnetic field produced
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