In a certain place on the surface of earth, angle of dip in a vertical plane ‘P’ is 300 . At the same place, angle of dip in another vertical plane ‘Q’ which is perpendicular to the plane. ‘P’, is 600. Then true angle of dip at that place is
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a
tan−123
b
tan−1710
c
tan−134
d
tan−1310
answer is D.
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Detailed Solution
If true angle of dip at that place is δ , thencot2δ = cot2δp+cot2δQ = cot2300+cot2600 = 3+13 = 103 ∴ δ = tan−1310Magnetic field produced