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In a certain planetary system, it is observed that one of the celestial bodies having a surface temperature of 200 K, emits radiation of maximum intensity near the wavelength 12μm. The surface temperature of a nearby star which emits light of maximum intensity at a wavelength λ=4800 Ao,is :

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Detailed Solution

λmT=constantλ1T1 = λ2T212μm × 200= 4800 AoTT=12 × 10−6 × 2004800 × 10−10 = 5000 K

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In a certain planetary system, it is observed that one of the celestial bodies having a surface temperature of 200 K, emits radiation of maximum intensity near the wavelength 12μm. The surface temperature of a nearby star which emits light of maximum intensity at a wavelength λ=4800 Ao,is :