Certain quantity of water cools from $$70$$°C to $$60$$°C in the first $$5$$ minutes and to $$54$$ °C in the next $$5$$ minutes. The temperature of the surroundings is:

Question

Infinity Learn · Accepted Answer

By newton's law of coolingθ$$1-$$θ$$2t=k$$θ$$1+$$θ$$22-$$θ$$0$$ ⇒   $$70-605=k70+602-$$θ$$0$$ ⇒              $$2=k65-$$θ$$0$$               ..(i) and         $$60-545=k$$ $$60+542-$$θ$$0$$ ⇒         $$65=k57-$$θ$$0$$                  ..(ii)By$$ dividing eqn.$$(i) by eqn.(ii) we have $$106=65-$$θ$$057-$$θ$$0$$⇒θ$$0=45o$$

Certain quantity of water cools from 70°C to 60°C in the first 5 minutes and to 54 °C in the next 5 minutes. The temperature of the surroundings is:

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