Certain quantity of water cools from 700C to 600C in the first 5 minutes and to 540C in the next 5 minutes. The temperature of the surroundings is
450C
200C
420C
100C
Newton's law of cooling
θ1-θ2∆t = K[θ1+θ22-θ0]
First ⇒ 70-605 = K[65-θ0]
⇒ 2 = K[65-θ0]------(i)
Next ⇒ 60-545 = K[57-θ0]------(ii)
Dividing (i) and (ii) 53 = 65-θ057-θ0
⇒ 285-5θ0-195-3θ0 ⇒ 2θ0 = 90
θ0 = 450