Download the app

Questions  

Certain quantity of water cools from 700C to 600C in the first 5 minutes and to 540C in the next 5 minutes. The temperature of the surroundings is

a
450C
b
200C
c
420C
d
100C

detailed solution

Correct option is A

Newton's law of cooling           θ1-θ2∆t = K[θ1+θ22-θ0]First ⇒ 70-605 = K[65-θ0]⇒ 2 = K[65-θ0]------(i)Next  ⇒ 60-545 = K[57-θ0]------(ii)Dividing (i) and (ii)   53 = 65-θ057-θ0⇒ 285-5θ0-195-3θ0   ⇒ 2θ0 = 90      θ0 = 450

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A calorimeter of mass 0.2 kg and specific heat 900 J/kg/K. Containing 0.5 kg of a liquid of specific heat 2400J/kg/K. Its temperature falls from 600C to 550C in one minute. Find the rate of cooling.


phone icon
whats app icon