Certain quantity of water cools from 70°C to 60°C in the first 5 minutes and to 54°C in the next 5 minutes. The temperature of the surroundings is
45°C
20°C
42°C
10°C
Let Ts be the temperature of the surroundings.
According to Newton's law of cooling
T1−T2t=KT1+T22−Ts
for first 5 minutes,
T1=70∘C,T2=60∘C,t=5 minutes ∴70−605=K70+602−Ts105=K65−Ts
T1=60∘C,T2=54∘C,t=5 minutes ∴ 60−545=K60+542−Ts65=K57−Ts
Divide eqn. (i) by eqn. (ii), we get
53=65−Ts57−Ts
285−5Ts=195−3Ts2Ts=90 or Ts=45∘C