Questions
Certain radio active substance reduces to 25% of its initial value in 16 days. Its half life is
a
32 days
b
8 days
c
64 days
d
28 days
detailed solution
Correct option is B
(2)N=N02t/t1/2 ⇒ N04=N02t/t1/2∴ 2t/t1/2 = 22 ⇒ tt1/2=2⇒ t1/2 = 72 =162 days=8 daysTalk to our academic expert!
Similar Questions
The half life period of a radioactive element X is same as the mean life time of another radioactive element Y. Initially both of them have the same number of atoms. Then
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