First slide

Radio activity

Question

Certain radio-active substance reduces to 25% of its value in 16 days. Its half-life is

Easy

A

32 days
B

8 days
C

64 days
D

28 days

Solution

$N = N_{0} {(\frac{1}{2})}^{\frac{t}{T}} \Rightarrow \frac{N_{0}}{4} = N_{0} {(\frac{1}{2})}^{\frac{16}{T}} \Rightarrow T = 8 days .$

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