In a certain region of space, the potential is given by : V=K2x2−y2+z2 The electric field at the point (1,1, 1) has magnitude =

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2K6

2K3

4K3

answer is B.

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Detailed Solution

E→=-δVδxi^-δVδyj^-δVδzk^ =-4kx i^ + 2ky j^ -2kz k^ At point (1,1,1) , E→ = -4k i^ +2k j^ -2k k^ ⇒E→ =26k

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