A cesium photocell, with a steady potential difference of 60 V across it, is illuminated by a small bright light placed 1 m away. When the same light is placed 2m away, the electrons crossing the photocell
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a
each carry one-quarter of their previous momentum
b
each carry one-quarter of their pervious energy
c
are one-quarter as numerous
d
are half as numerous
answer is C.
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Detailed Solution
I∝1/d2when source is placed 2 m away, then I′=(I/4). The number of electrons emitted ∝ intensity. Hence, the number of emitted electrons is reduced to one-fourth.