In CGS system, the Young's modulus of a steel wire is 2×1012 dyne/cm2. To double the length of a wire of unit cross-sectional area, the force required is
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a
4×106 dynes
b
2×1012dynes
c
2×1012newtons
d
2×108dynes
answer is B.
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Detailed Solution
To double the length of wire l=L, Stress = Young's modulus ∴ FA=2×1012dynecm2.If A = 1 then F = 2 × 1012 dyne
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In CGS system, the Young's modulus of a steel wire is 2×1012 dyne/cm2. To double the length of a wire of unit cross-sectional area, the force required is