A chain of mass M and length I is held vertical by fixing its upper end to a rigid support. The tension in the chain at a distance y from the rigid support is:
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a
mg
b
Mg(L - y)/L
c
MgL/(L - y)
d
Mgy/L
answer is B.
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Detailed Solution
Tension = Weight of hanging part=ML(L−y)g=Mg(L−y)/L