First slide

Different types of Forces

Question

A chain of mass M and length I is held vertical by fixing its upper end to a rigid support. The tension in the chain at a distance y from the rigid support is:

Easy

A

mg
B

Mg(L - y)/L
C

MgL/(L - y)
D

Mgy/L

Solution

Tension = Weight of hanging part
$\begin{array}{l} = [\frac{M}{L} (L - y)] g \\ = Mg (L - y) / L \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App