First slide

Work done by Diff type of forces

Question

A chain of mass m and length ‘L’ is over hanging from the edge of a smooth horizontal table such that 3/4th of its length is lying on the table. The work done in pulling the chain completely on to the table is

Moderate

A

mgL/16
B

mgL/32
C

3mgL/32
D

mgL/8

Solution

WORK done W = $\frac{M g l}{2 n^{2}}$ where l/n = length of the chain hanging at the edge
given l/n = l / 4
work done w= $\frac{M g l}{32}$

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