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A change of 8.0mA in the emitter current brings a change of 7.9mA in the collector current . Find the value  β.

a
79
b
89
c
59
d
69

detailed solution

Correct option is A

We have,               IE=IB+ICΔIE=ΔIB+ΔICFrom the question, when ΔIE=8.0 mA,ΔIC=7.9 mAThus,    ΔIB=8.0 mA−7.9 mA=0.1 mA                                    β=IcIB=ΔICΔIB =7.9 mA0.1 mA=79

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