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Q.

The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP  is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity  ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If  ΔT=CΔP then value of C in (K/atm.) is

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answer is 0150.00.

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Detailed Solution

At constant temperature PV=nRTPΔV+VΔP=0⇒ΔV=-VΔPP----(1) At constant pressure VT=nRP⇒V∝T⇒ΔVV=ΔTT⇒ΔV=V·ΔTT----(2)From equation(1) and equation(2)∵VΔTT=-VΔPP ⇒ΔTΔP=TP=3002=150
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The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP  is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity  ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If  ΔT=CΔP then value of C in (K/atm.) is