For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 34 d, where‘d’ is the separation between the plates of parallel plate capacitor. The new capacitance (C’) in terms of original capacitance (C0) is given by the following relation:

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C'=43+KC0

C'=3+K4KC0

C'=4KK+3C0

C'=4+K3C0

answer is C.

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Detailed Solution

C'=ε0At1k1+t2k2=ε0A3d4k+d4=4kε0A3+kd=4kC03+k

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