First slide

Electrostatic potential

Question

A charge of 5 C experiences a force of 5000 N, when it is moved in a uniform electric field. The potential difference between two points separated by a distance of 1 cm is

Moderate

Solution

$\begin{array}{rcl} E & = & \frac{F}{q} = \frac{5000}{5} = 1000 N / C \\ dV & = & E dx = 1000 x 10^{- 2} = 10 V \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App