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Q.

A charge of 1.1×10−4 C is placed inside a cylinder at the midpoint of the axis of the cylinder. The flux through one end of the cylinder is 4.5×106N−m2/C. What is the flux through ( the curved part of the cylinder's surface  in ×106Nm2C? Take the value of  ε0=8.8×10−12C2m2N

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answer is 3.5.

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Detailed Solution

The flux through the ends isϕ1=ϕ2=ϕ0 (let)and the flux through the curved surface is Φ.Then, the total flux  ϕ=2ϕ0+ϕ′=qε0ϕ′=qε0−2ϕ0=1.1×10−48.8×10−12−2×4.5×106=12.50×106−9×106=3.5×106Nm2C
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