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Q.

A charge of 10 e.s.u. is placed at a distance of 2 cm from a charge of 40 e.s.u. and 4 cm from another charge of 20 e.s.u. The potential energy of the charge 10 e.s.u. is (in ergs)

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a

87.5

b

112.5

c

150

d

250

answer is D.

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Detailed Solution

Energy =10×402+10×204=250 erg
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