Questions
A charge of 10 e.s.u. is placed at a distance of 2 cm from a charge of 40 e.s.u. and 4 cm from another charge of 20 e.s.u. The potential energy of the charge 10 e.s.u. is (in ergs)
detailed solution
Correct option is D
Energy =10×402+10×204=250ergTalk to our academic expert!
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Two equal point charges are fixed at x = - and x = + on the X-axis . Another point charge Q is placed at the origin. The change in electrical potential energy of Q when it is displaced by a small distance x along the X-axis, is approximately proportional to
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