First slide

Capacitance

Question

The charge on 4 $μ$ F capacitor in the given circuit is...in $μ$ C:

Moderate

A

12
B

24
C

36
D

32

Solution

Equivalent between A and B $= \frac{6 \times 4}{10} = 24 μF$
Hence charge across 4 $μ$ F (Since series combination charge remains constant) or 6 $μ$ F 24 x 10 = 24 $μ$ C

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