First slide

Pontial due to

Question

The charge given to a hollow sphere of radius 10 cm is 3.2 x l0^-19 coulomb. At a distance of 4 cm from its centre, the electric potential will be

Easy

A

28.8 x 10^-9volts
B

288 volts
C

2.88 volts
D

zero

Solution

Potential is to be determined at a distance of 4 cm from centre of sphere i. e., inside the sphere.
$V = \frac{kq}{r} = \frac{9 \times 10^{9} \times 3.2 \times 10^{- 19}}{10 \times 10^{- 2}} = 28.8 \times 10^{- 9} volts$

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