First slide

Electrostatic force

Question

A charge having magnitude Q is divided into two parts q and Q-q which are held a certain distance r apart. The force of repulsion between the two parts will be maximum if the ratio q/Q is

Moderate

Solution

$F = \frac{1}{4 {πε}_{0}} \frac{q (Q - q)}{r^{2}} F o r m a x i m u m f o r c e, \frac{d F}{d q} = 0 S i n c e r i s f i x e d w e h a v e \frac{d}{d q} (\frac{1}{4 {πε}_{0}} \frac{q (Q - q)}{r^{2}}) = 0 \frac{d}{d q} q (Q - q) = 0 w e g e t \frac{q}{Q} = \frac{1}{2} = 0.5$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App