A charge having magnitude Q is divided into two parts q and Q-q which are held a certain distance r apart. The force of repulsion between the two parts will be maximum if the ratio q/Q is
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answer is 0.5.
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Detailed Solution
F=14πε0qQ-qr2 For maximum force, dFdq=0 Since r is fixed we have ddq14πε0qQ-qr2=0 ddqqQ-q=0 we get qQ=12=0.5
A charge having magnitude Q is divided into two parts q and Q-q which are held a certain distance r apart. The force of repulsion between the two parts will be maximum if the ratio q/Q is