Questions
The charge on a parallel plate capacitor varies . The plates are very large and close together ( area of plates is A and separation is d) Neglecting the edge effects, the displacement current through the capacitor is
detailed solution
Correct option is B
Displacement current, ID=conduction current IC ID=IC=dqdt=ddtQo(sin2πft) ID=IC=Qo×2πfcos2πftTalk to our academic expert!
Similar Questions
A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
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