The charge on a parallel plate capacitor varies Q=Qosin2πft . The plates are very large and close together ( area of plates is A and separation is d) Neglecting the edge effects, the displacement current through the capacitor is
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a
Qo
b
Qo2πf cos 2πft
c
Qo cos 2πft
d
Zero
answer is B.
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Detailed Solution
Displacement current, ID=conduction current IC ID=IC=dqdt=ddtQo(sin2πft) ID=IC=Qo×2πfcos2πft