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Q.

A charge particle A of charge 2C has velocity 100 m/s. When it passes through point A and has velocity in the direction shown. The strength of magnetic field at point B due to this moving charge is (r = 2m)

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a

2.5µT

b

5.0µT

c

2.0µT

d

3.7µT

answer is A.

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Detailed Solution

B→=μo4πqV→X r→r3=μo4πqVsinθr2=10-7×2×100×0.5(2)2=2.5 x 10−6 T
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