First slide

Force on a charged particle moving in a magnetic field

Question

A charge particle of mass m and charge g travels on a circular path of radius r that is perpendicular to the magnetic. field B. The time taken by the particle to complete one revolution is

Easy

A

$\frac{2 πm}{qB}$
B

$\frac{2 πqB}{m}$
C

$\frac{2 πmq}{B}$
D

$\frac{2 {πq}^{2} B}{m}$

Solution

For magnetic field
$\frac{{mV}^{2}}{r} = qVB$
or $v = \frac{qBr}{m}$
Now T = $\frac{2 πr}{V} = \frac{2 πrm}{qBr} = \frac{2 πm}{qB}$

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