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Q.

A charge q=1μC  is placed at point (3m,2m,5m) . Find the electric field vector at point P (0m,−4m,3m) .

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a

−9343(3i^+6j^+2k^)kN/C

b

9343(3i^−6j^+k^)kN/C

c

3343(3i^+6j^+k^)kN/C

d

9343(3i^+6j^+2k^)kN/C

answer is A.

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Detailed Solution

E→=14πε0.q(r−r0)3(r→−r→0)  (r→−r→0)=(0−3)i^+(−4−2)j^+(3−5)k^=(−3i^−6j^−2k^)m|r→−r→0|=9+36+4=7m E→=9×109×1×10−673(−3i^−6j^−2k^)E→=−9×103343(3i^+6j^+2k^)|E→|=949×103N/C
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