A charge Q is distributed over two concentric conducting thin spherical shells radii r and R (R=n r). If the surface charge densities on the two shells are equal, the electric potential at the common centre is:
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a
14πε0r1-n1-n2Q
b
14πε0r1+n1+n2Q
c
14πε0r1+2nQ1+2n2
d
14πε0r1-2n1-2n2Q
answer is B.
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Detailed Solution
Let say inside shell has charge q1 and outside shell has charge q2.Surface charge densities are equal for both shells.⇒q14πr2=q24πR2 ⇒q1q2=r2R2→1 & q1+q2=Q→2∴q1=r2r2+R2Q & q2=R2R2+r2QPotential at common centre = V=Kq1r+Kq2R=KQrr2+R2+KQRR2+r2=KQr+Rr2+R2=KQr+nrr2+nr2=KQ1+nr1+n2