A charge ‘q’ is distributed over two concentric hollow conducting sphere of radii r and R (>r) such that their surface charge densites are equal. The potential at their common centre is
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a
Zero
b
q4π∈0(r+R)(r2+R2)2
c
q4π∈0[1r+1R]
d
q4π∈0[r+R(r2+R2)]
answer is D.
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Detailed Solution
Given (q−x)4πR2=x4πr2(q−x)=xR2r2q=x(R2+r2r2)x=q(r2R2+r2) ∴(q−x)=q(R2R2+r2)Common potential at centre=k[xr+q−xR]=14π∈0[r+RR2+r2]q