Q.
A charge Q is distributed over two concentric hollow spheres of radii r and R (>r) such that the surface densities are equal. The potential at the common centre is
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a
QR2+r24πε0(R+r)
b
QR+r
c
zero
d
Q(R+r)4πε0R2+r2
answer is D.
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Detailed Solution
Let the charges on spheres of radii r and R be q1 and q2 respectively. Then Q = q1+ q2. The potential at the centre will be V=14πε0q1r+q2RAs surface densities are equal, henceσ=q14πr2=q24πR2 or q2=q1R2/r2∴ V=14πε0q1r+q1Rr2=14πε0×q1r2[r+R]Now, q1+q2=Q or q1+q1R2r2=Q∴ q1r2=QR2+r2So, V=Q4πε0R+rR2+r2
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