A charge Q is distributed over two concentric hollow spheres of radii r and (R>r) such that the surface densities are equal. The potential at the common center is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Q(R2+r2)4πε0(R+r)
b
QR+r
c
Zero
d
Q(R+r)4πε0(R2+r2)
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
If q1 and q2 are the charge on spheres of radius r and R, respectively, in accordance with conservation of charge,Q=q1+q2 ….. (i)and according to the given problem, σ1=σ2i.e, q14πr2=q24πR2⇒ q1q2=r2R2 …… (ii)So, (i) and (ii) giveq1=Qr2(R2+r2) and q2=QR2(R2+r2)Potential at common centerV=14πε0[q1r+q2R]=14πε0[Qr(R2+r2)+QR(R2+r2)]=14πε0.Q(R+r)(R2+r2)