A charge q is enclosed by an imaginary Gaussian surface.If radius of surface is increasing at the rate drdt = K, then
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
flux linked with surface is increasing at the rate dϕdt=K
b
flux linked with surface is decreasing at the rate dϕdt=-K
c
flux linked with surface is decreasing at the rate dϕdt=1K
d
flux linked with surface is qεo
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
From Gauss' law ϕ=qenclosedεo in which qenclosed is the net charge inside an imaginary closed surface (a Gaussian surface) flux does not depend on the radius of imaginary enclosed surface.