Q.

Charge Q1  and  Q2 are at points A and B of a right   angle triangle OAB (see fig). The resultant electric field at point O is perpendicular to the hypotenuse, then  Q1/  Q2 is proportional to:

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a

x13x23

b

x22x12

c

x2 x1

d

x1 x2

answer is D.

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Detailed Solution

E1sinθ=E2cosθ​kQ1x12sinθ=kQ2x22cosθ​Q1Q2=x1x22cotθ=x1x2
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Charge Q1  and  Q2 are at points A and B of a right   angle triangle OAB (see fig). The resultant electric field at point O is perpendicular to the hypotenuse, then  Q1/  Q2 is proportional to: