Q.
Charge Q1 and Q2 are at points A and B of a right angle triangle OAB (see fig). The resultant electric field at point O is perpendicular to the hypotenuse, then Q1/ Q2 is proportional to:
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a
x13x23
b
x22x12
c
x2 x1
d
x1 x2
answer is D.
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Detailed Solution
E1sinθ=E2cosθkQ1x12sinθ=kQ2x22cosθQ1Q2=x1x22cotθ=x1x2
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