A charge ‘q’ is placed at the centre of the line joining two equal charges ‘Q’. The system of the three charges will be in equilibrium if ‘q’ is equal to
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a
-Q/4
b
Q/4
c
-Q/2
d
Q/2
answer is A.
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Detailed Solution
The situation is as shown in the figure.Let two equal charges Q each placed at points A and B at a distance r apart. C is the centre of A B where charge q is placed. For equilibrium, net force on charge Q=0∴ 14πε0QQr2+14πε0Qq(r/2)2=0 14πε0Q2r2=-14πε04Qqr2 or Q=-4q or q=-Q4