Questions
A charged capacitor of capacitance C and having charge Q is to be connected with another uncharged capacitor of capacitance through a resistor R as shown in figure. The value of for heat liberated in R to be minimum is :
detailed solution
Correct option is D
Common potential = QC+C1Liberated heatH=Q22C-12C+C1QC+C12 =Q22C-Q22(C+C1)=Q2C12C(C+C1)which is minimum at C1 = 0 (It means open circuit).Talk to our academic expert!
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A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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