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Questions  

A charged particle is accelerated through a potential difference of 100V passes through crossed electric and magnetic fields without any deflection. IfE=15×106V/m  and B=5×103T.  Then the specific charge of the particle is

 

a
9×105C/Kg
b
4.5×104C/Kg
c
176×1011C/Kg
d
27×109C/Kg

detailed solution

Correct option is B

em=υ22V, υ=EB       =ε22VB2=(15×106)22(100)(5×103)2       =4.5×104c/kg

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