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Q.

A charged particle is accelerated through a potential difference of 100V passes through crossed electric and magnetic fields without any deflection. IfE=15×106V/m  and B=5×103T.  Then the specific charge of the particle is

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a

9×105C/Kg

b

4.5×104C/Kg

c

176×1011C/Kg

d

27×109C/Kg

answer is B.

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Detailed Solution

em=υ22V, υ=EB       =ε22VB2=(15×106)22(100)(5×103)2       =4.5×104c/kg
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