Q.

A charged particle carrying a charge 2µC is fired in a gravity free space where mutually perpendicular electric and magnetic field exist. If  E→=3i^-3j^v/m  and B→=ai^+5j^ Tesla and the particle passes undeviated, then magnitude of magnetic field is

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

52 T

b

72T

c

4 T

d

92T

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

V→×B→+QE→=0⇒E→=QV→×B→Therefore E→ and B→ must be mutually perpendicular. i.e. E→. B→ = 0 ⇒3i^-3j^.ai^-5j^=0⇒3a-15=0⇒a=5∴B=52+52T=52T
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon