Q.
A charged particle carrying a charge 2µC is fired in a gravity free space where mutually perpendicular electric and magnetic field exist. If E→=3i^-3j^v/m and B→=ai^+5j^ Tesla and the particle passes undeviated, then magnitude of magnetic field is
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
52 T
b
72T
c
4 T
d
92T
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
V→×B→+QE→=0⇒E→=QV→×B→Therefore E→ and B→ must be mutually perpendicular. i.e. E→. B→ = 0 ⇒3i^-3j^.ai^-5j^=0⇒3a-15=0⇒a=5∴B=52+52T=52T
Watch 3-min video & get full concept clarity