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Q.

A charged particle carrying a charge 2µC is fired in a gravity free space where mutually perpendicular electric and magnetic field exist. If  E→=3i^-3j^v/m  and B→=ai^+5j^ Tesla and the particle passes undeviated, then magnitude of magnetic field is

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a

52 T

b

72T

c

4 T

d

92T

answer is A.

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Detailed Solution

V→×B→+QE→=0⇒E→=QV→×B→Therefore E→ and B→ must be mutually perpendicular. i.e. E→. B→ = 0 ⇒3i^-3j^.ai^-5j^=0⇒3a-15=0⇒a=5∴B=52+52T=52T
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