Questions
A charged particle carrying a charge 2µC is fired in a gravity free space where mutually perpendicular electric and magnetic field exist. If and and the particle passes undeviated, then magnitude of magnetic field is
detailed solution
Correct option is A
V→×B→+QE→=0⇒E→=QV→×B→Therefore E→ and B→ must be mutually perpendicular. i.e. E→. B→ = 0 ⇒3i^-3j^.ai^-5j^=0⇒3a-15=0⇒a=5∴B=52+52T=52TTalk to our academic expert!
Similar Questions
A charged particle of mass m, carrying a charge Q is projected from the origin with a velocity . A uniform magnetic field exists in that region. Then maximum distance of the particle from x-axis is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
