A charged particle carrying a charge $$+Q$$ is fixed at point $$0$$, A uniform magnetic field of induction B→ exists in the region which points out of the plane of the page. An electron is projected from point P with velocity V→ as shown in the figure. Then path of the electron

Question

A charged particle carrying a charge $$+Q$$ is fixed at point $$0$$, A uniform magnetic field of induction B→ exists in the region which points out of the plane of the page. An electron is projected from point P with velocity V→ as shown in the figure. Then path of the electron

Infinity Learn · Accepted Answer

From the diagram it is evident that electric force $$F=14$$π∈$$oQe(OP)2$$ acting on the electron is radially inward and the magnetic force F→$$=-eV$$→×B→ is also radially inward. Therefore net force acting on the electron is always radially in ward and always perpendicular to the direction of motion. Hence the path is a circle.

A charged particle carrying a charge +Q is fixed at point 0, A uniform magnetic field of induction $\vec{B}$ exists in the region which points out of the plane of the page. An electron is projected from point P with velocity $\vec{V}$ as shown in the figure. Then path of the electron

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A charged particle carrying a charge +Q is fixed at point 0, A uniform magnetic field of induction B→ exists in the region which points out of the plane of the page. An electron is projected from point P with velocity V→ as shown in the figure. Then path of the electron

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A charged particle carrying a charge +Q is fixed at point 0, A uniform magnetic field of induction $\vec{B}$ exists in the region which points out of the plane of the page. An electron is projected from point P with velocity $\vec{V}$ as shown in the figure. Then path of the electron