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Q.

A charged particle, carrying a charge Q moves with velocity 2 m/s in x-y plane in a uniform magnetic field  B→=i^+2j^+3k^T.Then magnitude of component of magnetic force experienced by the particle is zero

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Detailed Solution

v→=ai^+bj^(a and b are non-zero quantities).∴  F→B =  Qv→  ×  B→=Q  i^j^k^ab0123=Q  3bi^−3aj^+2a−bk^
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