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Force on a charged particle moving in a magnetic field

Question

A charged particle, carrying a charge Q moves with velocity 2 m/s in x-y plane in a uniform magnetic field  B=i^+2j^+3k^T.Then magnitude of component of magnetic force experienced by the particle is zero

Moderate
Solution

v=ai^+bj^(a and b are non-zero quantities).

  FB=  Qv  ×  B=Q  i^j^k^ab0123=Q  3bi^3aj^+2abk^



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