A charged particle, carrying a charge Q moves with velocity 2 m/s in x-y plane in a uniform magnetic field B→=i^+2j^+3k^T.Then magnitude of component of magnetic force experienced by the particle is zero

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answer is 4.

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Detailed Solution

v→=ai^+bj^(a and b are non-zero quantities).∴ F→B = Qv→ × B→=Q i^j^k^ab0123=Q 3bi^−3aj^+2a−bk^

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