A charged particle (charge q) is moving in a circle of radius R with uniform speed v. The associated magnetic moment μ is given by
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a
qvR2
b
qvR2
c
qvR22
d
qvR
answer is A.
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Detailed Solution
As revolving charge is equivalent to a current loop, so electric current corresponds to the revolution of electron is I=q f=q × ω2πBut ω=vR, where R is radius of circle and v is uniform speed of charged particle. Therefore, I=qv2πRNow, magnetic moment associated with charged particle is given byor μ=qv2πR × πR2 = 12 qvR