Q.

A charged particle (charge q) is moving in a circle of radius R with uniform speed v. The associated magnetic moment μ is given by

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a

qvR2

b

qvR2

c

qvR22

d

qvR

answer is A.

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Detailed Solution

As revolving charge is equivalent to a current loop, so electric current corresponds to the revolution of electron is I=q  f=q  ×  ω2πBut ω=vR,  where R is radius of circle and v is uniform speed of charged particle. Therefore, I=qv2πRNow, magnetic moment associated with charged particle is given byor      μ=qv2πR  ×  πR2 = 12  qvR
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