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Q.

A charged particle enters into uniform magnetic field with velocity  v0 perpendicular to it. The length of magnetic field is x=32R, where R is the radius of the circular path of the particle in the field. The magnitude of change in velocity of the particle when it comes out of the field is  nV0. Find the value of n.

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Detailed Solution

Deviation θ=sin−1LR=sin−132=600Δv→=2v0sinθ2=2v0sin300=v0
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A charged particle enters into uniform magnetic field with velocity  v0 perpendicular to it. The length of magnetic field is x=32R, where R is the radius of the circular path of the particle in the field. The magnitude of change in velocity of the particle when it comes out of the field is  nV0. Find the value of n.