A charged particle enters a uniform magnetic field with velocity $$v0$$ perpendicular to it. The length of magnetic field is $$x=32$$ R, where R is the radius of the circular path of the particle in the field. The magnitude of change in velocity of the particle when it comes out of the field is

Question

A charged particle enters a uniform magnetic field with velocity $$v0$$ perpendicular to it. The length of magnetic field is $$x=32$$  R, where R is the radius of the circular path of the particle in the field. The magnitude of change in velocity of the particle when it comes out of the field is

Infinity Learn · Accepted Answer

The particle will come out of the magnetic field at an angle θ$$=600$$ with the original direction.Δv→$$=$$ $$v0$$ $$cos$$  $$60i^$$  $$+$$  $$v0$$ $$sin$$  $$60j^$$ −$$v0i^$$⇒   Δv→ $$=$$  $$v0$$

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A charged particle enters a uniform magnetic field with velocity v0 perpendicular to it. The length of magnetic field is x=32 R, where R is the radius of the circular path of the particle in the field. The magnitude of change in velocity of the particle when it comes out of the field is

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