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Questions  

A charged particle enters a uniform magnetic field with velocity vector at an angle of 45° with the magnetic field. The pitch of the helical path followed by the particle is p. The radius of the helix will be

a
p2π
b
2p
c
p2π
d
2pπ

detailed solution

Correct option is C

p = 2πmBq  v cos 450 = 2πmBq   v sin 450∴     mvsin 450Bq  =  p2π= radius of helix

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