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Q.

A charged particle enters a uniform magnetic field with a velocity vector at an angle 450 with the magnetic field. The pitch of the helical path followed by the particle is p , the radius of the helix will be

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a

p2π

b

2p

c

p2π

d

2pπ

answer is C.

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Detailed Solution

Pitch=p=(vcosθ)T   r=mvsinθqB   and T=2πmqB solving we get r=p2π
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