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A charged particle enters a uniform magnetic field with a velocity vector at an angle 450 with the magnetic field. The pitch of the helical path followed by the particle is p , the radius of the helix will be 

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a
p2π
b
2p
c
p2π
d
2pπ

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detailed solution

Correct option is C

Pitch=p=(vcosθ)T   r=mvsinθqB   and T=2πmqB solving we get r=p2π

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