A charged particle enters a uniform magnetic field with a velocity vector at an angle 450 with the magnetic field. The pitch of the helical path followed by the particle is p , the radius of the helix will be

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p2π

2pπ

answer is C.

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Detailed Solution

Pitch=p=(vcosθ)T r=mvsinθqB and T=2πmqB solving we get r=p2π

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