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Q.

A charged particle going around in a circle can be considered to be a current loop. A particle of mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field B→. The magnetic moment of this moving particle :

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a

−mv2B→B2

b

−mv2B→2B2

c

−mv2B→2πB2

d

mv2B→2B2

answer is B.

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Detailed Solution

Let q is positive and B→ is into the plane So charge particle is moving in anticlockwise sense on a circle of radius r=mϑqBHence magnetic moment μ=i×πr2=q2πrϑ×πr2=qϑr2=mϑ22BClearly magnetic moment is out of the plane so μ→=−mϑ22B2×B→

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A charged particle going around in a circle can be considered to be a current loop. A particle of mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field B→. The magnetic moment of this moving particle :