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Motion of a charged particle

Question

A charged particle having charge 10-6 C and mass of 10-10 kg is fired at the middle of the plate making an angle 30° with plane of the plate. Length of the plate is 0. 17 m and it is separated by 0.1 m. Electric field E=10-3 N/C is present between the plates. Just outside the plates magnetic field is present. Find the magnitude of the magnetic field (in mT)perpendicular to the plane of the figure, if it has to graze the plate at C and A (in mT) parallel to the surface of the plate.(Neglect gravity)

Moderate
Solution

To graze at C
Using equation of trajectory of parabola,

y=xtanθ-ax22v2cos2θ          (i)  Here, a=qEm=10-6×10-310-10=10 m/s2 Substituting in equation (i), we have  0.05=0.17tan30°-10×(0.17)22v2×(3/2)2

Solving this equation, we have v - 2 m/s
In magnetic field, AC - Zr

or 0.1 = 2r

or r=0.05m=mvcos30°Bq   B=mvcos30°(0.05)q=10-10(2)(3/2)(0.05)10-6 =3.46×10-3 T=3.46mT



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A uniform electric field E is present horizontally along the paper throughout region but uniform magnetic field B0 is present horizontally (perpendicular to plane of paper in inward direction) right to the line AB as shown. A charge particle having charge q and mass m is projected vertically upward and crosses the line AB after time t0. The speed of projection if particle moves after t0 with constant velocity. (given qE = mg) is nto. Find the value of ‘n’. (g = 9.8 m/s2)


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