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Q.

A charged particle having drift velocity of 7.5×10−4m s−1 in an electric field of 3×10−10Vm−1, has a mobility in m2V−1s−1 of

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a

2.5×106

b

2.5×10−6

c

2.25×10−15

d

2.25×1015

answer is A.

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Detailed Solution

μ=VdE=7.5x10−43x10−10μ=2.5x106
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