A charged particle of mass 4 gm and having a charge +1 μC is fired from a point with speed 10 m/s where electric potential is 4x105 V in the direction where electric potential is decreasing, find the potential at a point (in x 105 volts) where its speed becomes 102 m/s m/s. Express your answer in multiple of 105.

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answer is 2.

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Detailed Solution

Work done by electric field = gain in KE of the particle.qV2-V1=12mv22-v21⇒ 1×10−64×105−V=12×4×10−3×[1022−102]⇒ V=2×105V

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