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Q.

A charged particle of mass m, carrying a charge Q is projected from the origin with a velocity V→=Voi^+j^. A uniform magnetic field B→=Bi^ exists in that region. Then maximum distance of the particle from x-axis is

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a

2mvoQB

b

mvoQB

c

mvo2QB

d

2mvoQB

answer is A.

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Detailed Solution

The trajectory of the particle is a helix. Angular velocity ω=QBm and radius r=Vow=mVoQB.So maximum distance from x-axis = 2r =2mVoQB
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A charged particle of mass m, carrying a charge Q is projected from the origin with a velocity V→=Voi^+j^. A uniform magnetic field B→=Bi^ exists in that region. Then maximum distance of the particle from x-axis is