First slide

Motion of charged particle in uniform electric field

Question

A charged particle of mass m and charge Q is released from rest from the position $(x_{0}, 0)$ in a uniform electric field $' E_{0} \hat{j}' .$ The angular momentum of the particle about origin

Moderate

A

is zero
B

is constant
C

increases with time
D

decreases with time

Solution

After release, the particle will start moving along the line AB with increasing speed. Speed at time ‘t’ is
$\begin{array}{l} v = (\frac{Q E}{m}) t \\ ∴ L_{0} = m v . x_{0} = (Q E x_{0}) t \end{array}$

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